PSD.12:5.1.1 - A separate constructed delay-response question
Keep the preceding probability and value-reversal question separate. For this new illustration, fix a thirty-day service window and one access interruption. A stipulated model supplies the service-loss hours for F and M at three access delays; lower service loss is preferred. Each arrangement and all other modeled conditions stay fixed while delay varies.
| Access delay in days | F: service-loss hours | M: service-loss hours |
|---|---|---|
| 0 | 2 | 1 |
| 1 | 2.5 | 3 |
| 2 | 3 | 9 |
With x = 1 day and h = 1 day, M’s central response is 3 hours, its endpoint mean is (1 + 9)/2 = 5 hours, and D = 2 hours. F’s central response and endpoint mean are both 2.5 hours, so its D = 0. F has no midpoint gap at these three points; this does not establish a linear response between them.
Under the separately declared four-hour service-loss criterion, M’s two-day response of 9 hours fails. F satisfies that criterion at the three stated points only. Neither endpoint mean is an expected real loss without a probability basis, and a central response below four hours does not settle the endpoint test.
The useful return is the finite response difference, M’s failure condition and the remaining model and coverage limits. F’s additional investment and the feasibility of any alternative access protection still need their whole-configuration comparison. If the stipulated model lacks support for real use, retain the calculation as conditional or illustrative; do not report an established pump-performance result. No additional observations or investment are authorized by it.